Find using differentials the approximate area of a square whose side is 3.01 cm .
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Find using differentials the approximate area of a square whose side is 3.01 cm .
Solution For Find using differentials the approximate area of a square whose side is 3.01 \mathrm{~cm}.
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Question 1 (a) - Using differentials, find approximate value of (17/81
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Use differentials to find an approximate value for the given number
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SOLVED: Use differentials to approximate the given values by hand. Provide decimal digits of accuracy. Note: Only use a calculator for routine arithmetic (addition, subtraction, multiplication, division) as part of the approximation by differentials. If you use your calculator to obtain a result directly (i.e., taking powers or roots), then your answer may be different than the requested approximation.V16.09 V15.95V8.06 179T
SOLVED: Use differentials to approximate the given values by hand. Provide decimal digits of accuracy. Note: Only use a calculator for routine arithmetic (addition, subtraction, multiplication, division) as part of the approximation by differentials. If you use your calculator to obtain a result directly (i.e., taking powers or roots), then your answer may be different than the requested approximation.V16.09 V15.95V8.06 179T
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Question 1 (a) - Using differentials, find approximate value of (17/81
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9 个月之前
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Use differentials to find an approximate value for the given number
Use differentials to find an approximate value for the given n…
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SOLVED: Use differentials to approximate the given values by hand. Provide decimal digits of accuracy. Note: Only use a calculator for routine arithmetic (addition, subtraction, multiplication, division) as part of the approximation by differentials. If you use your calculator to obtain a result directly (i.e., taking powers or roots), then your answer may be different than the requested approximation.V16.09 V15.95V8.06 179T
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Approximate the area of a rectangle of dimensions 35.02 by 24.97 units. For dimensions x by y, the area is A=x y so that d A=(∂A)/(∂x) d x (∂A)/(∂y) d y=y d x x d y. With x=35, d x=0.02, y=25, and d y=-0.03, we have A=35(25)=875 and d A=25(0.02) 35(-0.03)=-0.55. The area is approximately A d A=874.45 square units. | Numerade
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