The inequality will be solved when \({m}\) is isolated on one side of the inequality. This can be done by using inverse operations on each stage of the sum. The final answer is ...

Let 0 < mI ≤ A ≤ m′I ≤ M′I ≤ B ≤ MI and p ≥ 1. Then for every positive unital linear map Φ, Φ 2p ( A ∇ t B )≤ ( K( h,2 ) 4 1 p −1 ( 1+Q( t ) ( log M' m' ) 2 ) ) 2p Φ 2p ( A ♯ t B ) Φ 2p ( A ∇ t B )≤ ( ...

Inequalities are the relationships between two expressions which are not equal to one another. The symbols used for inequalities are <, >, ≤, ≥. \(7 \textgreater x\) reads as '7 is greater than \(x\)' ...